Verwenden Sie einfach file:
$ file /usr/bin/add-apt-repository
/usr/bin/add-apt-repository: Python script, ASCII text executable
$ file /usr/bin/ab
/usr/bin/ab: ELF 64-bit LSB shared object, x86-64, version 1 (SYSV), dynamically linked (uses shared libs), for GNU/Linux 2.6.32, BuildID[sha1]=569314a9c4458e72e4ac66cb043e9a1fdf0b55b7, stripped
Wie erklärt in man file:
NAME
file — determine file type
DESCRIPTION
This manual page documents version 5.14 of the file command.
file tests each argument in an attempt to classify it. There are three
sets of tests, performed in this order: filesystem tests, magic tests,
and language tests. The first test that succeeds causes the file type to
be printed.
The type printed will usually contain one of the words text (the file
contains only printing characters and a few common control characters and
is probably safe to read on an ASCII terminal), executable (the file con‐
tains the result of compiling a program in a form understandable to some
UNIX kernel or another), or data meaning anything else (data is usually
“binary” or non-printable). Exceptions are well-known file formats (core
files, tar archives) that are known to contain binary data. When adding
local definitions to /etc/magic, make sure to preserve these keywords.
Users depend on knowing that all the readable files in a directory have
the word “text” printed. Don't do as Berkeley did and change “shell
commands text” to “shell script”.
Sie können auch einen Trick verwenden, um dies direkt auf den Namen der ausführbaren Datei in Ihrem auszuführen $PATH:
$ file $(type -p add-apt-repository | awk '{print $NF}')
/usr/local/bin/add-apt-repository: Python script, ASCII text executable
$ file $(type -p ab | awk '{print $NF}')
/usr/bin/ab: ELF 64-bit LSB shared object, x86-64, version 1 (SYSV), dynamically linked (uses shared libs), for GNU/Linux 2.6.32, BuildID[sha1]=569314a9c4458e72e4ac66cb043e9a1fdf0b55b7, stripped
So ermitteln Sie den Dateityp aller ausführbaren Dateien, die sich in Ihren Verzeichnissen $PATHbefinden:
find $(printf "$PATH" | sed 's/:/ /g') -type f | xargs file
Und um filealle Dateien in einem bestimmten Verzeichnis ( /usr/binzum Beispiel) auszuführen , tun Sie dies einfach
file /usr/bin/*
filefür jede Datei ausführen, um zu sehen, um welchen Dateityp es sich handelt. Gibt es eine einfache Methode für alle Dateien?