Senden von HTML-E-Mails mit Python

Wie kann ich den HTML-Inhalt mit Python in einer E-Mail senden? Ich kann einfachen Text senden.

Aus der Python v2.7.14-Dokumentation - 18.1.11. E-Mail: Beispiele :

Hier ist ein Beispiel für das Erstellen einer HTML-Nachricht mit einer alternativen Nur-Text-Version:

#! /usr/bin/python

import smtplib

from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

# me == my email address
# you == recipient's email address
me = "my@email.com"
you = "your@email.com"

# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = "Link"
msg['From'] = me
msg['To'] = you

# Create the body of the message (a plain-text and an HTML version).
text = "Hi!\nHow are you?\nHere is the link you wanted:\nhttp://www.python.org"
html = """\
<html>
  <head></head>
  <body>
    <p>Hi!<br>
       How are you?<br>
       Here is the <a href="http://www.python.org">link</a> you wanted.
    </p>
  </body>
</html>
"""

# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')

# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)

# Send the message via local SMTP server.
s = smtplib.SMTP('localhost')
# sendmail function takes 3 arguments: sender's address, recipient's address
# and message to send - here it is sent as one string.
s.sendmail(me, you, msg.as_string())
s.quit()

Sie könnten versuchen, meine zu verwenden Mailer- Modul zu verwenden.

from mailer import Mailer
from mailer import Message

message = Message(From="me@example.com",
                  To="you@example.com")
message.Subject = "An HTML Email"
message.Html = """<p>Hi!<br>
   How are you?<br>
   Here is the <a href="http://www.python.org">link</a> you wanted.</p>"""

sender = Mailer('smtp.example.com')
sender.send(message)

Hier ist eine Google Mail- Implementierung der akzeptierten Antwort:

import smtplib

from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

# me == my email address
# you == recipient's email address
me = "my@email.com"
you = "your@email.com"

# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = "Link"
msg['From'] = me
msg['To'] = you

# Create the body of the message (a plain-text and an HTML version).
text = "Hi!\nHow are you?\nHere is the link you wanted:\nhttp://www.python.org"
html = """\
<html>
  <head></head>
  <body>
    <p>Hi!<br>
       How are you?<br>
       Here is the <a href="http://www.python.org">link</a> you wanted.
    </p>
  </body>
</html>
"""

# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')

# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
mail = smtplib.SMTP('smtp.gmail.com', 587)

mail.ehlo()

mail.starttls()

mail.login('userName', 'password')
mail.sendmail(me, you, msg.as_string())
mail.quit()

Hier ist eine einfache Möglichkeit, eine HTML-E-Mail zu senden, indem Sie den Content-Type-Header als 'text / html' angeben:

import email.message
import smtplib

msg = email.message.Message()
msg['Subject'] = 'foo'
msg['From'] = 'sender@test.com'
msg['To'] = 'recipient@test.com'
msg.add_header('Content-Type','text/html')
msg.set_payload('Body of <b>message</b>')

# Send the message via local SMTP server.
s = smtplib.SMTP('localhost')
s.starttls()
s.login(email_login,
        email_passwd)
s.sendmail(msg['From'], [msg['To']], msg.as_string())
s.quit()

Hier ist Beispielcode. Dies ist inspiriert von Code auf der Python Cookbook- Website (der genaue Link kann nicht gefunden werden).

def createhtmlmail (html, text, subject, fromEmail):
    """Create a mime-message that will render HTML in popular
    MUAs, text in better ones"""
    import MimeWriter
    import mimetools
    import cStringIO

    out = cStringIO.StringIO() # output buffer for our message 
    htmlin = cStringIO.StringIO(html)
    txtin = cStringIO.StringIO(text)

    writer = MimeWriter.MimeWriter(out)
    #
    # set up some basic headers... we put subject here
    # because smtplib.sendmail expects it to be in the
    # message body
    #
    writer.addheader("From", fromEmail)
    writer.addheader("Subject", subject)
    writer.addheader("MIME-Version", "1.0")
    #
    # start the multipart section of the message
    # multipart/alternative seems to work better
    # on some MUAs than multipart/mixed
    #
    writer.startmultipartbody("alternative")
    writer.flushheaders()
    #
    # the plain text section
    #
    subpart = writer.nextpart()
    subpart.addheader("Content-Transfer-Encoding", "quoted-printable")
    pout = subpart.startbody("text/plain", [("charset", 'us-ascii')])
    mimetools.encode(txtin, pout, 'quoted-printable')
    txtin.close()
    #
    # start the html subpart of the message
    #
    subpart = writer.nextpart()
    subpart.addheader("Content-Transfer-Encoding", "quoted-printable")
    #
    # returns us a file-ish object we can write to
    #
    pout = subpart.startbody("text/html", [("charset", 'us-ascii')])
    mimetools.encode(htmlin, pout, 'quoted-printable')
    htmlin.close()
    #
    # Now that we're done, close our writer and
    # return the message body
    #
    writer.lastpart()
    msg = out.getvalue()
    out.close()
    print msg
    return msg

if __name__=="__main__":
    import smtplib
    html = 'html version'
    text = 'TEST VERSION'
    subject = "BACKUP REPORT"
    message = createhtmlmail(html, text, subject, 'From Host <sender@host.com>')
    server = smtplib.SMTP("smtp_server_address","smtp_port")
    server.login('username', 'password')
    server.sendmail('sender@host.com', 'target@otherhost.com', message)
    server.quit()

Verbessern Sie für Python3 die Antwort von @taltman :

• Verwenden Sie email.message.EmailMessageanstelle von email.message.Message, um E-Mails zu erstellen.
• benutze email.set_contentfunc, weise subtype='html'argument zu. anstelle von Low-Level-Funktion set_payloadund Header manuell hinzufügen.
• Verwenden Sie SMTP.send_messagefunc anstelle von SMTP.sendmailfunc, um E-Mails zu senden.
• Verwenden Sie den withBlock, um die Verbindung automatisch zu schließen.

from email.message import EmailMessage
from smtplib import SMTP

# construct email
email = EmailMessage()
email['Subject'] = 'foo'
email['From'] = 'sender@test.com'
email['To'] = 'recipient@test.com'
email.set_content('<font color="red">red color text</font>', subtype='html')

# Send the message via local SMTP server.
with smtplib.SMTP('localhost') as s:
    s.login('foo_user', 'bar_password')
    s.send_message(email)

Eigentlich hat yagmail einen etwas anderen Ansatz gewählt.

Es wird standardmäßig senden HTML, mit automatischem Rückfall für unfähig E - Mail-Leser. Es ist nicht mehr das 17. Jahrhundert.

Natürlich kann es überschrieben werden, aber hier geht's:

import yagmail
yag = yagmail.SMTP("me@example.com", "mypassword")

html_msg = """<p>Hi!<br>
              How are you?<br>
              Here is the <a href="http://www.python.org">link</a> you wanted.</p>"""

yag.send("to@example.com", "the subject", html_msg)

Installationsanweisungen und viele weitere großartige Funktionen finden Sie im Github .

Hier ist ein funktionierendes Beispiel zum Senden von Nur-Text- und HTML-E-Mails von Python mit smtplib zusammen mit den CC- und BCC-Optionen.

https://varunver.wordpress.com/2017/01/26/python-smtplib-send-plaintext-and-html-emails/

#!/usr/bin/env python
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

def send_mail(params, type_):
      email_subject = params['email_subject']
      email_from = "from_email@domain.com"
      email_to = params['email_to']
      email_cc = params.get('email_cc')
      email_bcc = params.get('email_bcc')
      email_body = params['email_body']

      msg = MIMEMultipart('alternative')
      msg['To'] = email_to
      msg['CC'] = email_cc
      msg['Subject'] = email_subject
      mt_html = MIMEText(email_body, type_)
      msg.attach(mt_html)

      server = smtplib.SMTP('YOUR_MAIL_SERVER.DOMAIN.COM')
      server.set_debuglevel(1)
      toaddrs = [email_to] + [email_cc] + [email_bcc]
      server.sendmail(email_from, toaddrs, msg.as_string())
      server.quit()

# Calling the mailer functions
params = {
    'email_to': 'to_email@domain.com',
    'email_cc': 'cc_email@domain.com',
    'email_bcc': 'bcc_email@domain.com',
    'email_subject': 'Test message from python library',
    'email_body': '<h1>Hello World</h1>'
}
for t in ['plain', 'html']:
    send_mail(params, t)

Hier ist meine Antwort für AWS mit boto3

    subject = "Hello"
    html = "<b>Hello Consumer</b>"

    client = boto3.client('ses', region_name='us-east-1', aws_access_key_id="your_key",
                      aws_secret_access_key="your_secret")

client.send_email(
    Source='ACME <do-not-reply@acme.com>',
    Destination={'ToAddresses': [email]},
    Message={
        'Subject': {'Data': subject},
        'Body': {
            'Html': {'Data': html}
        }
    }

Einfachste Lösung zum Senden von E-Mails von einem Organisationskonto in Office 365:

from O365 import Message

html_template =     """ 
            <html>
            <head>
                <title></title>
            </head>
            <body>
                    {}
            </body>
            </html>
        """

final_html_data = html_template.format(df.to_html(index=False))

o365_auth = ('sender_username@company_email.com','Password')
m = Message(auth=o365_auth)
m.setRecipients('receiver_username@company_email.com')
m.setSubject('Weekly report')
m.setBodyHTML(final_html_data)
m.sendMessage()

hier df ein Datenrahmen, der in eine HTML-Tabelle konvertiert wurde und in html_template eingefügt wird