JavaScript-Array neu strukturieren

const users = [{ id: 1, name: 'John', email: 'johnson@mail.com', age: 25, parent_address: 'USA', relationship: 'mother' }, { id: 1, name: 'John', email: 'johnson@mail.com', age: 25, parent_address: 'Spain', relationship: 'father' }, { id: 2, name: 'Mark', email: 'mark@mail.com', age: 28, parent_address: 'France', relationship: 'father' } ];
const res = Object.values(users.reduce((acc, {parent_address, relationship, ...r}) => { // use destructuring assignment to pull out necessary values
  acc[r.id] = acc[r.id] || {...r, parents: []}
  acc[r.id].parents.push({parent_address, relationship}); // short-hand property names allows us to use the variable names as keys
  return acc;
}, {}));

console.log(res);

const users = [{ id: 1, name: 'John', email: 'johnson@mail.com', age: 25, parent_address: 'USA', relationship: 'mother' }, { id: 1, name: 'John', email: 'johnson@mail.com', age: 25, parent_address: 'Spain', relationship: 'father' }, { id: 2, name: 'Mark', email: 'mark@mail.com', age: 28, parent_address: 'France', relationship: 'father' } ];

const unique_map = {}; // create an object - store each id as a key, and an object with a parents array as its value
for(let i = 0; i < users.length; i++) { // loop your array object
  const user = users[i]; // get the current object
  const id = user.id; // get the current object/users's id
  
  if(!(id in unique_map)) // check if current user's id is in the the object
    unique_map[id] = { // add the id to the unique_map with an object as its associated value 
      id: id,
      name: user.name,
      email: user.email,
      age: user.age,
      parents: [] // add `parents` array to append to later
    }
    
  unique_map[id].parents.push({ // push the parent into the object's parents array
    parent_address: user.parent_address,
    relationship: user.relationship
  });
}

const result = Object.values(unique_map); // get all values in the unique_map
console.log(result);

const
    users = [{ id: 1, name: 'John', email: 'johnson@mail.com', age: 25, parent_address: 'USA', relationship: 'mother' }, { id: 1, name: 'John', email: 'johnson@mail.com', age: 25, parent_address: 'Spain', relationship: 'father' }, { id: 2, name: 'Mark', email: 'mark@mail.com', age: 28, parent_address: 'France', relationship: 'father' }],
    grouped = users.reduce((r, { parent_address, relationship, ...user }) => {
        var temp = r.find(q => q.id === user.id );
        if (!temp) r.push(temp = { ...user, parent: []});
        temp.parent.push({ parent_address, relationship });
        return r;
    }, []);

console.log(grouped);

.as-console-wrapper { max-height: 100% !important; top: 0; }

const users = [{
    id: 1,
    name: 'John',
    email: 'johnson@mail.com',
    age: 25,
    parent_address: 'USA',
    relationship:'mother'
  },
  {
    id: 1,
    name: 'John',
    email: 'johnson@mail.com',
    age: 25,
    parent_address: 'Spain',
    relationship:'father'
  },
  {
    id: 2,
    name: 'Mark',
    email: 'mark@mail.com',
    age: 28,
    parent_address: 'France',
    relationship:'father'
  }
];

let combined = users.reduce(
  // function called for each element in the array
  (previous, element) => {
    // previous starts out as the empty object we pass as the second argument
    // and will be the return value from this function for every other element
    
    // create an object for the id on our 'previous' object if it doesn't exist,
    // if it does exist we will trust the name, email, and age from the first
    // instance
    previous[element.id] = previous[element.id] || {
      id: element.id,
      name: element.name,
      age: element.age,
      parents: []
    };
    
    // now add parent
    previous[element.id].parents.push({
      parent_address: element.parent_address,
      relationship: element.relationship
    });
    
    // return our updated object, which will be passed to the next call
    // and eventually returned
    return previous;
  },
  {} // initial value is an empty object, no ids yet
);

// transform object into array with elements in order by key
let list = Object.keys(combined).sort().map(key => combined[key]);

console.dir(list);

const users = [
  {
    id: 1,
    name: 'John',
    email: 'johnson@mail.com',
    age: 25,
    parent_address: 'USA',
    relationship: 'mother'
  },
  {
    id: 1,
    name: 'John',
    email: 'johnson@mail.com',
    age: 25,
    parent_address: 'Spain',
    relationship: 'father'
  },
  {
    id: 2,
    name: 'Mark',
    email: 'mark@mail.com',
    age: 28,
    parent_address: 'France',
    relationship: 'father'
  }
];

const unique = new Map(users.map(u=> 
    [u.id, {...u, parent: [...users.filter(f => f.id == u.id)]}]));

console.log(Array.from(unique, ([k, v])=> v).map(s => ( 
    { id: s.id, name: s.name, email: s.email, age:s.age, parent:s.parent })));

 const users = [{
    id: 1,
    name: 'John',
    email: 'johnson@mail.com',
    age: 25,
    parent_address: 'USA',
    relationship:'mother'
  },
  {
    id: 1,
    name: 'John',
    email: 'johnson@mail.com',
    age: 25,
    parent_address: 'Spain',
    relationship:'father'
  },
  {
    id: 2,
    name: 'Mark',
    email: 'mark@mail.com',
    age: 28,
    parent_address: 'France',
    relationship:'father'
  }
];
ids = new Map()
for (const user of users) {
  var newuser;
  if (ids.has(user.id)) {
    newuser = ids.get(user.id);
  } else {
    newuser = {};
    newuser.id = user.id;
    newuser.name = user.name;
    newuser.email = user.email;
    newuser.age = user.age;
    newuser.parent = [];
  }
  relationship = {};
  relationship.parent_address = user.parent_address;
  relationship.relationship = user.relationship;
  newuser.parent.push(relationship)
  ids.set(user.id, newuser);
}
list = [ ...ids.values() ];
list.forEach((u) => {
  console.log(JSON.stringify(u));
});