Wie finde ich die Dauer der Differenz zwischen zwei Daten in Java?

Ich habe zwei Objekte von DateTime , die die Dauer ihrer Differenz ermitteln müssen.

Ich habe den folgenden Code, bin mir aber nicht sicher, wie ich ihn fortsetzen soll, um zu den erwarteten Ergebnissen zu gelangen:

Beispiel

      11/03/14 09:30:58
      11/03/14 09:33:43
      elapsed time is 02 minutes and 45 seconds
      -----------------------------------------------------
      11/03/14 09:30:58 
      11/03/15 09:30:58
      elapsed time is a day
      -----------------------------------------------------
      11/03/14 09:30:58 
      11/03/16 09:30:58
      elapsed time is two days
      -----------------------------------------------------
      11/03/14 09:30:58 
      11/03/16 09:35:58
      elapsed time is two days and 05 mintues

Code

    String dateStart = "11/03/14 09:29:58";
    String dateStop = "11/03/14 09:33:43";

    Custom date format
    SimpleDateFormat format = new SimpleDateFormat("yy/MM/dd HH:mm:ss");

    Date d1 = null;
    Date d2 = null;
    try {
        d1 = format.parse(dateStart);
        d2 = format.parse(dateStop);
    } catch (ParseException e) {
        e.printStackTrace();
    }

    // Get msec from each, and subtract.
    long diff = d2.getTime() - d1.getTime();
    long diffSeconds = diff / 1000 % 60;
    long diffMinutes = diff / (60 * 1000) % 60;
    long diffHours = diff / (60 * 60 * 1000);
    System.out.println("Time in seconds: " + diffSeconds + " seconds.");
    System.out.println("Time in minutes: " + diffMinutes + " minutes.");
    System.out.println("Time in hours: " + diffHours + " hours.");

Versuche Folgendes

{
        Date dt2 = new DateAndTime().getCurrentDateTime();

        long diff = dt2.getTime() - dt1.getTime();
        long diffSeconds = diff / 1000 % 60;
        long diffMinutes = diff / (60 * 1000) % 60;
        long diffHours = diff / (60 * 60 * 1000);
        int diffInDays = (int) ((dt2.getTime() - dt1.getTime()) / (1000 * 60 * 60 * 24));

        if (diffInDays > 1) {
            System.err.println("Difference in number of days (2) : " + diffInDays);
            return false;
        } else if (diffHours > 24) {

            System.err.println(">24");
            return false;
        } else if ((diffHours == 24) && (diffMinutes >= 1)) {
            System.err.println("minutes");
            return false;
        }
        return true;
}

Die Datumsdifferenzkonvertierung könnte mit der in Java integrierten Klasse TimeUnit besser gehandhabt werden . Es bietet Dienstprogrammmethoden, um dies zu tun:

Date startDate = // Set start date
Date endDate   = // Set end date

long duration  = endDate.getTime() - startDate.getTime();

long diffInSeconds = TimeUnit.MILLISECONDS.toSeconds(duration);
long diffInMinutes = TimeUnit.MILLISECONDS.toMinutes(duration);
long diffInHours = TimeUnit.MILLISECONDS.toHours(duration);
long diffInDays = TimeUnit.MILLISECONDS.toDays(duration);

Verwenden Sie die Joda-Time- Bibliothek

DateTime startTime, endTime;
Period p = new Period(startTime, endTime);
long hours = p.getHours();
long minutes = p.getMinutes();

Joda Time hat ein Konzept des Zeitintervalls:

Interval interval = new Interval(oldTime, new Instant());

Ein weiteres Beispiel Datumsunterschied

Noch ein Link

oder mit Java-8 (das Joda-Time-Konzepte integriert hat)

Instant start, end;//
Duration dur = Duration.between(start, stop);
long hours = dur.toHours();
long minutes = dur.toMinutes();

So kann das Problem in Java 8 gelöst werden, genau wie die Antwort von shamimz.

Quelle: http://docs.oracle.com/javase/tutorial/datetime/iso/period.html

LocalDate today = LocalDate.now();
LocalDate birthday = LocalDate.of(1960, Month.JANUARY, 1);

Period p = Period.between(birthday, today);
long p2 = ChronoUnit.DAYS.between(birthday, today);

System.out.println("You are " + p.getYears() + " years, " + p.getMonths() + " months, and " + p.getDays() + " days old. (" + p2 + " days total)");

Der Code erzeugt eine Ausgabe ähnlich der folgenden:

You are 53 years, 4 months, and 29 days old. (19508 days total)

Wir müssen LocalDateTime http://docs.oracle.com/javase/8/docs/api/java/time/LocalDateTime.html verwenden , um Unterschiede zwischen Stunden, Minuten und Sekunden zu erhalten.

Date d2 = new Date();
Date d1 = new Date(1384831803875l);

long diff = d2.getTime() - d1.getTime();
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000);
int diffInDays = (int) diff / (1000 * 60 * 60 * 24);

System.out.println(diffInDays+"  days");
System.out.println(diffHours+"  Hour");
System.out.println(diffMinutes+"  min");
System.out.println(diffSeconds+"  sec");

Sie können eine Methode wie erstellen

public long getDaysBetweenDates(Date d1, Date d2){
return TimeUnit.MILLISECONDS.toDays(d1.getTime() - d2.getTime());
}

Diese Methode gibt die Anzahl der Tage zwischen den beiden Tagen zurück.

Wie Michael Borgwardt in seiner Antwort hier schreibt :

int diffInDays = (int)( (newerDate.getTime() - olderDate.getTime()) 
                 / (1000 * 60 * 60 * 24) )

Beachten Sie, dass dies mit UTC-Daten funktioniert. Wenn Sie sich die lokalen Daten ansehen, kann der Unterschied ein freier Tag sein. Und damit es mit lokalen Daten richtig funktioniert, ist aufgrund der Sommerzeit ein völlig anderer Ansatz erforderlich.

In Java 8 können Sie von machen DateTimeFormatter, Durationund LocalDateTime. Hier ist ein Beispiel:

final String dateStart = "11/03/14 09:29:58";
final String dateStop = "11/03/14 09:33:43";

final DateTimeFormatter formatter = new DateTimeFormatterBuilder()
        .appendValue(ChronoField.MONTH_OF_YEAR, 2)
        .appendLiteral('/')
        .appendValue(ChronoField.DAY_OF_MONTH, 2)
        .appendLiteral('/')
        .appendValueReduced(ChronoField.YEAR, 2, 2, 2000)
        .appendLiteral(' ')
        .appendValue(ChronoField.HOUR_OF_DAY, 2)
        .appendLiteral(':')
        .appendValue(ChronoField.MINUTE_OF_HOUR, 2)
        .appendLiteral(':')
        .appendValue(ChronoField.SECOND_OF_MINUTE, 2)
        .toFormatter();

final LocalDateTime start = LocalDateTime.parse(dateStart, formatter);
final LocalDateTime stop = LocalDateTime.parse(dateStop, formatter);

final Duration between = Duration.between(start, stop);

System.out.println(start);
System.out.println(stop);
System.out.println(formatter.format(start));
System.out.println(formatter.format(stop));
System.out.println(between);
System.out.println(between.get(ChronoUnit.SECONDS));

Es hat funktioniert, ich kann es versuchen, hoffe, es wird hilfreich sein. Lassen Sie mich wissen, wenn Sie Bedenken haben.

Date startDate = java.util.Calendar.getInstance().getTime(); //set your start time
Date endDate = java.util.Calendar.getInstance().getTime(); // set  your end time

long duration = endDate.getTime() - startDate.getTime();


long diffInSeconds = TimeUnit.MILLISECONDS.toSeconds(duration);
long diffInMinutes = TimeUnit.MILLISECONDS.toMinutes(duration);
long diffInHours = TimeUnit.MILLISECONDS.toHours(duration);
long diffInDays = TimeUnit.MILLISECONDS.toDays(duration);

Toast.makeText(MainActivity.this, "Diff"
        + duration + diffInDays + diffInHours + diffInMinutes + diffInSeconds, Toast.LENGTH_SHORT).show(); **// Toast message for android .**

System.out.println("Diff" + duration + diffInDays + diffInHours + diffInMinutes + diffInSeconds); **// Print console message for Java .**

Dies ist der Code:

        String date1 = "07/15/2013";
        String time1 = "11:00:01";
        String date2 = "07/16/2013";
        String time2 = "22:15:10";
        String format = "MM/dd/yyyy HH:mm:ss";
        SimpleDateFormat sdf = new SimpleDateFormat(format);
        Date fromDate = sdf.parse(date1 + " " + time1);
        Date toDate = sdf.parse(date2 + " " + time2);

        long diff = toDate.getTime() - fromDate.getTime();
        String dateFormat="duration: ";
        int diffDays = (int) (diff / (24 * 60 * 60 * 1000));
        if(diffDays>0){
            dateFormat+=diffDays+" day ";
        }
        diff -= diffDays * (24 * 60 * 60 * 1000);

        int diffhours = (int) (diff / (60 * 60 * 1000));
        if(diffhours>0){
            dateFormat+=diffhours+" hour ";
        }
        diff -= diffhours * (60 * 60 * 1000);

        int diffmin = (int) (diff / (60 * 1000));
        if(diffmin>0){
            dateFormat+=diffmin+" min ";
        }
        diff -= diffmin * (60 * 1000);

        int diffsec = (int) (diff / (1000));
        if(diffsec>0){
            dateFormat+=diffsec+" sec";
        }
        System.out.println(dateFormat);

und das raus ist:

duration: 1 day 11 hour 15 min 9 sec

In Bezug auf Shamims Antwort-Update handelt es sich hier um eine Methode, die die Aufgabe ohne Verwendung einer Bibliothek eines Drittanbieters ausführt. Kopieren Sie einfach die Methode und verwenden Sie

public static String getDurationTimeStamp(String date) {

        String timeDifference = "";

        //date formatter as per the coder need
        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

        //parse the string date-ti
        // me to Date object
        Date startDate = null;
        try {
            startDate = sdf.parse(date);
        } catch (ParseException e) {
            e.printStackTrace();
        }

        //end date will be the current system time to calculate the lapse time difference
        //if needed, coder can add end date to whatever date
        Date endDate = new Date();

        System.out.println(startDate);
        System.out.println(endDate);

        //get the time difference in milliseconds
        long duration = endDate.getTime() - startDate.getTime();

        //now we calculate the differences in different time units
        //this long value will be the total time difference in each unit
        //i.e; total difference in seconds, total difference in minutes etc...
        long diffInSeconds = TimeUnit.MILLISECONDS.toSeconds(duration);
        long diffInMinutes = TimeUnit.MILLISECONDS.toMinutes(duration);
        long diffInHours = TimeUnit.MILLISECONDS.toHours(duration);
        long diffInDays = TimeUnit.MILLISECONDS.toDays(duration);

        //now we create the time stamps depending on the value of each unit that we get
        //as we do not have the unit in years,
        //we will see if the days difference is more that 365 days, as 365 days = 1 year
        if (diffInDays > 365) {
            //we get the year in integer not in float
            //ex- 791/365 = 2.167 in float but it will be 2 years in int
            int year = (int) (diffInDays / 365);
            timeDifference = year + " years ago";
            System.out.println(year + " years ago");
        }
        //if days are not enough to create year then get the days
        else if (diffInDays > 1) {
            timeDifference = diffInDays + " days ago";
            System.out.println(diffInDays + " days ago");
        }
        //if days value<1 then get the hours
        else if (diffInHours > 1) {
            timeDifference = diffInHours + " hours ago";
            System.out.println(diffInHours + " hours ago");
        }
        //if hours value<1 then get the minutes
        else if (diffInMinutes > 1) {
            timeDifference = diffInMinutes + " minutes ago";
            System.out.println(diffInMinutes + " minutes ago");
        }
        //if minutes value<1 then get the seconds
        else if (diffInSeconds > 1) {
            timeDifference = diffInSeconds + " seconds ago";
            System.out.println(diffInSeconds + " seconds ago");
        }

        return timeDifference;
// that's all. Happy Coding :)
    }

Dies ist ein Programm, das ich geschrieben habe und das die Anzahl der Tage zwischen zwei Daten ermittelt (hier keine Zeit).

import java.util.Scanner;
public class HelloWorld {
 public static void main(String args[]) {
  Scanner s = new Scanner(System.in);
  System.out.print("Enter starting date separated by dots: ");
  String inp1 = s.nextLine();
  System.out.print("Enter ending date separated by dots: ");
  String inp2 = s.nextLine();
  int[] nodim = {
   0,
   31,
   28,
   31,
   30,
   31,
   30,
   31,
   31,
   30,
   31,
   30,
   31
  };
  String[] inpArr1 = split(inp1);
  String[] inpArr2 = split(inp2);
  int d1 = Integer.parseInt(inpArr1[0]);
  int m1 = Integer.parseInt(inpArr1[1]);
  int y1 = Integer.parseInt(inpArr1[2]);
  int d2 = Integer.parseInt(inpArr2[0]);
  int m2 = Integer.parseInt(inpArr2[1]);
  int y2 = Integer.parseInt(inpArr2[2]);
  if (y1 % 4 == 0) nodim[2] = 29;
  int diff = m1 == m2 && y1 == y2 ? d2 - (d1 - 1) : (nodim[m1] - (d1 - 1));
  int mm1 = m1 + 1, mm2 = m2 - 1, yy1 = y1, yy2 = y2;
  for (; yy1 <= yy2; yy1++, mm1 = 1) {
   mm2 = yy1 == yy2 ? (m2 - 1) : 12;
   if (yy1 % 4 == 0) nodim[2] = 29;
   else nodim[2] = 28;
   if (mm2 == 0) {
    mm2 = 12;
    yy2 = yy2 - 1;
   }
   for (; mm1 <= mm2 && yy1 <= yy2; mm1++) diff = diff + nodim[mm1];
  }
  System.out.print("No. of days from " + inp1 + " to " + inp2 + " is " + diff);
 }
 public static String[] split(String s) {
  String[] retval = {
   "",
   "",
   ""
  };
  s = s + ".";
  s = s + " ";
  for (int i = 0; i <= 2; i++) {
   retval[i] = s.substring(0, s.indexOf("."));
   s = s.substring((s.indexOf(".") + 1), s.length());
  }
  return retval;
 }
}

http://pastebin.com/HRsjTtUf

Ich habe das ähnliche Problem kürzlich mit einer einfachen Methode gelöst.

public static void main(String[] args) throws IOException, ParseException {
        TimeZone utc = TimeZone.getTimeZone("UTC");
        Calendar calendar = Calendar.getInstance(utc);
        Date until = calendar.getTime();
        calendar.add(Calendar.DAY_OF_MONTH, -7);
        Date since = calendar.getTime();
        long durationInSeconds  = TimeUnit.MILLISECONDS.toSeconds(until.getTime() - since.getTime());

        long SECONDS_IN_A_MINUTE = 60;
        long MINUTES_IN_AN_HOUR = 60;
        long HOURS_IN_A_DAY = 24;
        long DAYS_IN_A_MONTH = 30;
        long MONTHS_IN_A_YEAR = 12;

        long sec = (durationInSeconds >= SECONDS_IN_A_MINUTE) ? durationInSeconds % SECONDS_IN_A_MINUTE : durationInSeconds;
        long min = (durationInSeconds /= SECONDS_IN_A_MINUTE) >= MINUTES_IN_AN_HOUR ? durationInSeconds%MINUTES_IN_AN_HOUR : durationInSeconds;
        long hrs = (durationInSeconds /= MINUTES_IN_AN_HOUR) >= HOURS_IN_A_DAY ? durationInSeconds % HOURS_IN_A_DAY : durationInSeconds;
        long days = (durationInSeconds /= HOURS_IN_A_DAY) >= DAYS_IN_A_MONTH ? durationInSeconds % DAYS_IN_A_MONTH : durationInSeconds;
        long months = (durationInSeconds /=DAYS_IN_A_MONTH) >= MONTHS_IN_A_YEAR ? durationInSeconds % MONTHS_IN_A_YEAR : durationInSeconds;
        long years = (durationInSeconds /= MONTHS_IN_A_YEAR);

        String duration = getDuration(sec,min,hrs,days,months,years);
        System.out.println(duration);
    }
    private static String getDuration(long secs, long mins, long hrs, long days, long months, long years) {
        StringBuffer sb = new StringBuffer();
        String EMPTY_STRING = "";
        sb.append(years > 0 ? years + (years > 1 ? " years " : " year "): EMPTY_STRING);
        sb.append(months > 0 ? months + (months > 1 ? " months " : " month "): EMPTY_STRING);
        sb.append(days > 0 ? days + (days > 1 ? " days " : " day "): EMPTY_STRING);
        sb.append(hrs > 0 ? hrs + (hrs > 1 ? " hours " : " hour "): EMPTY_STRING);
        sb.append(mins > 0 ? mins + (mins > 1 ? " mins " : " min "): EMPTY_STRING);
        sb.append(secs > 0 ? secs + (secs > 1 ? " secs " : " secs "): EMPTY_STRING);
        sb.append("ago");
        return sb.toString();
    }

Und wie erwartet druckt es : 7 days ago.

   // calculating the difference b/w startDate and endDate
        String startDate = "01-01-2016";
        String endDate = simpleDateFormat.format(currentDate);

        date1 = simpleDateFormat.parse(startDate);
        date2 = simpleDateFormat.parse(endDate);

        long getDiff = date2.getTime() - date1.getTime();

        // using TimeUnit class from java.util.concurrent package
        long getDaysDiff = TimeUnit.MILLISECONDS.toDays(getDiff);

So berechnen Sie die Differenz zwischen zwei Daten in Java